16x^2=400x-1360

Solution for 16x^2=400x-1360 equation:

16x^2=400x-1360

We move all terms to the left:

16x^2-(400x-1360)=0

We get rid of parentheses

16x^2-400x+1360=0

a = 16; b = -400; c = +1360;
Δ = b2-4ac
Δ = -4002-4·16·1360
Δ = 72960
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{72960}=\sqrt{256*285}=\sqrt{256}*\sqrt{285}=16\sqrt{285}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-400)-16\sqrt{285}}{2*16}=\frac{400-16\sqrt{285}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-400)+16\sqrt{285}}{2*16}=\frac{400+16\sqrt{285}}{32}
$